Application Presets
System Parameters
Economic Analysis
Typical: $10-20/kVAR
Typical: $0.08-0.15/kWh
Capacitor Requirements
Required Capacitor Bank
Power Factor Improvement
Economic Benefits
Return on Investment
Calculation Steps
1. Real Power: 100 kW = 100000 W
2. Current power factor: 0.7 (70.0%)
3. Current reactive power (Q1): 100000 × tan(cos⁻¹(0.7)) = 102020.41 VAR
4. Target power factor: 0.95 (95.0%)
5. Target reactive power (Q2): 100000 × tan(cos⁻¹(0.95)) = 32868.41 VAR
6. Required capacitor: Qc = Q1 - Q2
7. Qc = 102.02 - 32.87 = 69.15 kVAR
8. Capacitance: C = Qc / (2π × f × V²)
9. C = 69151.99560415442 / (2π × 50 × 380²) = 1.524e-3 F
10. C = 1524.36 µF
11. kVA Reduction: 142.86 - 105.26 = 37.59 kVA
12. Improved power factor reduces utility demand charges!
Benefits of PF Correction
Important Notes
• Do not over-correct (PF > 1.0 creates leading power factor issues)
• Use automatic PF controllers for variable loads
• Install harmonic filters if non-linear loads present
• Consider detuned capacitors for systems with VFDs
• Annual maintenance required (check capacitor condition)